2=(2/2x^2)

Solution for 2=(2/2x^2) equation:

2=(2/2x^2)

We move all terms to the left:

2-((2/2x^2))=0


Domain of the equation: 2x^2))!=0

x!=0/1

x!=0

x∈R


We multiply all the terms by the denominator


-((2+2*2x^2))=0


We calculate terms in parentheses: -((2+2*2x^2)), so:

(2+2*2x^2)

We get rid of parentheses

2*2x^2+2

Wy multiply elements

4x^2+2

Back to the equation:

-(4x^2+2)


We get rid of parentheses

-4x^2-2=0

a = -4; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·(-4)·(-2)
Δ = -32
Delta is less than zero, so there is no solution for the equation